Repeated subtraction of consecutive odd numbers from 81 gives: 81 - 1 = 80, 80 - 3 = 77, 77 - 5 = 72, ... until 0 is reached. How many subtractions are needed, and what does this tell you about √81?

Question

Accepted Answer

9 subtractions, √81 = 9. Subtracting odd numbers 1, 3, 5, 7, 9, 11, 13, 15, 17 from 81 reaches 0 in 9 steps. The number of subtractions equals the square root, so √81 = 9.

Repeated subtraction of consecutive odd numbers from 81 gives:
81 - 1 = 80, 80 - 3 = 77, 77 - 5 = 72, ... until 0 is reached.
How many subtractions are needed, and what does this tell you about
$81$ ?

Step-by-Step Solution

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More Class 8 Finding Square Roots practice

Repeated subtraction of consecutive odd numbers from 81 gives:81 - 1 = 80, 80 - 3 = 77, 77 - 5 = 72, ... until 0 is reached.How many subtractions are needed, and what does this tell you about81​?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 8 Finding Square Roots practice

Repeated subtraction of consecutive odd numbers from 81 gives:
81 - 1 = 80, 80 - 3 = 77, 77 - 5 = 72, ... until 0 is reached.
How many subtractions are needed, and what does this tell you about
$81$ ?