- A180°
- B45°
- C120°
- D90°
Step-by-Step Solution
∠A + ∠D = 180°, so half of each adds to 90°. In triangle APD, ∠APD = 180° − 90° = 90°.
Answer: D) 90°
In trapezium ABCD with AB ∥ DC, the bisectors of ∠A and ∠D meet at P. What is ∠APD?
Class 8Kites and TrapeziumsQuadrilaterals
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