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The top angle ∠D of isosceles trapezium ABCD (AB ∥ DC, AD = BC) is 124°. Find the bottom angle ∠B.

Class 8Kites and TrapeziumsQuadrilaterals
  • A34°
  • B124°
  • C56°
  • D66°

Step-by-Step Solution

∠A = 180° − 124° = 56° (co-interior with ∠D). Base angles are equal, so ∠B = ∠A = 56°.
Answer: C) 56°

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