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The curved surface of a cylinder of radius 7 cm and height 12 cm is cut open along its height and flattened out. What are the dimensions of the rectangle formed? Use π = .

Class 8MensurationMensuration
  • A22 cm × 12 cm
  • B7 cm × 12 cm
  • C44 cm × 12 cm
  • D154 cm × 12 cm

Step-by-Step Solution

Unrolling turns the curved surface into a rectangle whose width is the base CIRCUMFERENCE and whose other side is the height. Circumference = 2π cm, so the rectangle is 44 cm × 12 cm (area = the CSA). Trap 22 cm: using π instead of 2π. Trap 7 cm: using the radius itself as the width. Trap 154 cm: using the base AREA π as a length.
Answer: C) 44 cm × 12 cm

Key idea: Surface area and volume of a cylinder

A cylinder is a circle stacked vertically. Two measurements: radius and height .

**Curved surface area (CSA) = 2π** (imagine 'unrolling' the curved surface — it becomes a rectangle of width 2π and height h).

**Total surface area (TSA) = 2πππ** (curved surface + two circular ends).

**Volume = π** (area of circular base × height).

Use π = 22/7 when is a multiple of 7; otherwise π ≈ 3.14.

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