- A13
- B7
- C25
- D24
Step-by-Step Solution
The number must be 1 more than a common multiple of 2, 3 and 4. LCM = 12, so the number is 12 + 1 = 13.
Answer: A) 13
What is the smallest number greater than 1 that leaves a remainder of 1 when divided by 2, by 3 and by 4?
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