n^3 can be written as the sum of n consecutive odd numbers. If a block of consecutive odd numbers sums to 343 in this pattern, how many odd numbers are in that block?

Question

Accepted Answer

7. 343 = 7^3, and n^3 is the sum of n consecutive odd numbers, so the block has 7 odd numbers.

$n^{3}$ can be written as the sum of $n$ consecutive odd numbers.
If a block of consecutive odd numbers sums to 343 in this pattern, how many odd numbers are in that block?

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More Class 8 Patterns in Cubes practice

n3 can be written as the sum of n consecutive odd numbers.If a block of consecutive odd numbers sums to 343 in this pattern, how many odd numbers are in that block?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 8 Patterns in Cubes practice

$n^{3}$ can be written as the sum of $n$ consecutive odd numbers.
If a block of consecutive odd numbers sums to 343 in this pattern, how many odd numbers are in that block?