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Find the smallest number by which 135 must be divided so that the quotient is a perfect cube $. (135 = 3 \times 3 \times 3 \times 5.)$

Class 8Perfect CubesCubes and Roots

A3
B5
C9
D15

Step-by-Step Solution

135 =

3^{3} \times

5. The extra factor 5 prevents a cube, so divide by 5:

135/5 = 27 = 3^{3}

.

Answer: B) 5

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