A trapezium has vertices P(0, 0), Q(8, 0), R(6, 4) and S(2, 4), each unit being 1 cm. The two parallel sides are PQ and SR. Using area = 1/2 x (sum of parallel sides) x height, find the area in square cm.

Question

Accepted Answer

24. PQ = 8 - 0 = 8 cm; SR = 6 - 2 = 4 cm. Height (gap between the parallel sides) = 4 - 0 = 4 cm. Area = 1/2 x (8 + 4) x 4 = 1/2 x 12 x 4 = 24 sq cm.

A trapezium has vertices P(0, 0), Q(8, 0), R(6, 4) and S(2, 4), each unit being 1 cm. The two parallel sides are PQ and SR.
Using area = $\frac{1}{2} x$ (sum of parallel sides) $x$ height, find the area in square cm.

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More Class 8 Plotting Points practice

A trapezium has vertices P(0, 0), Q(8, 0), R(6, 4) and S(2, 4), each unit being 1 cm. The two parallel sides are PQ and SR.Using area = 21​x (sum of parallel sides) x height, find the area in square cm.

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 8 Plotting Points practice

A trapezium has vertices P(0, 0), Q(8, 0), R(6, 4) and S(2, 4), each unit being 1 cm. The two parallel sides are PQ and SR.
Using area = $\frac{1}{2} x$ (sum of parallel sides) $x$ height, find the area in square cm.