A spinner is divided into sectors red, blue, green and yellow. P(red) = 1/4, P(blue) = 1/3 and P(green) = 1/6. What is the probability of landing on yellow?

Question

Accepted Answer

1/4. Sum = 1. P(yellow) = 1 - 1/4 - 1/3 - 1/6. LCD 12: 1 = 12/12; 3/12 + 4/12 + 2/12 = 9/12. Yellow = 3/12 = 1/4.

A spinner is divided into sectors red, blue, green and yellow.
P(red) = $\frac{1}{4}$ , P(blue) = $\frac{1}{3}$ and P(green) = $\frac{1}{6}$ .
What is the probability of landing on yellow?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 8 Probability practice

A spinner is divided into sectors red, blue, green and yellow.P(red) = 41​, P(blue) = 31​ and P(green) = 61​.What is the probability of landing on yellow?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 8 Probability practice

A spinner is divided into sectors red, blue, green and yellow.
P(red) = $\frac{1}{4}$ , P(blue) = $\frac{1}{3}$ and P(green) = $\frac{1}{6}$ .
What is the probability of landing on yellow?