Two consecutive multiples of 5 are such that one-fifth of the smaller equals one-tenth of the larger plus 1. If the smaller is 5n, set up and reduce the equation to find the smaller multiple.

Question

Accepted Answer

15. Smaller = 5n, larger = 5n + 5. Then 5n/5 = 5n + 5/10 + 1, so n = n + 1/2 + 1. Multiply by 2: 2n = n + 1 + 2, so n = 3, giving smaller = 15.

Two consecutive multiples of 5 are such that one-fifth of the smaller equals one-tenth of the larger plus 1.
If the smaller is $5 n$ , set up and reduce the equation to find the smaller multiple.

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