Find the LEAST number that must be SUBTRACTED from 6412 to make it a perfect square. (Use long division to find the remainder.)

Question

Accepted Answer

12. By long division, √6412: 80^2 = 6400 <= 6412 and 81^2 = 6561 > 6412. The remainder after 80 is 6412 - 6400 = 12. Subtract 12 to get the perfect square 6400 = 80^2.

Find the LEAST number that must be SUBTRACTED from 6412 to make it a perfect square. (Use long division to find the remainder.)

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