In a long division of a 6-digit perfect square, the quotient (square root) comes out to a 3-digit number. The first period from the left is 14 and the first quotient digit is 3 (since 3^2 = 9, with 4^2 = 16 too big). If the complete number is 144400, what is its square root?

Question

Accepted Answer

380. Pair: 14 44 00. 3^2 = 9, rem 5 -> 544; 68*8 = 544, rem 0 -> 0000; double 38 = 76, 760*0 = 0. So √144400 = 380.

In a long division of a 6-digit perfect square, the quotient (square root) comes out to a 3-digit number. The first period from the left is 14 and the first quotient digit is 3 (since $3^{2} = 9$ , with $4^{2} = 16$ too big).
If the complete number is 144400, what is its square root?

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More Class 8 Square Root by Long Division practice

In a long division of a 6-digit perfect square, the quotient (square root) comes out to a 3-digit number. The first period from the left is 14 and the first quotient digit is 3 (since 32=9, with 42=16 too big).If the complete number is 144400, what is its square root?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 8 Square Root by Long Division practice

In a long division of a 6-digit perfect square, the quotient (square root) comes out to a 3-digit number. The first period from the left is 14 and the first quotient digit is 3 (since $3^{2} = 9$ , with $4^{2} = 16$ too big).
If the complete number is 144400, what is its square root?