In the long division for √4489, the first divisor is 6 (since 6^2 = 36) for the period 44. What is the very next divisor used (before placing the next digit)?

Question

Accepted Answer

12. After the first digit 6, the new divisor starts as double of the quotient so far: 2 * 6 = 12. We then look for a digit x so that 12x * x fits. (67*7 = 469 gives √4489 = 67.)

In the long division for $4489$ , the first divisor is 6 (since $6^{2} = 36$ ) for the period 44. What is the very next divisor used (before placing the next digit)?

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More Class 8 Square Root by Long Division practice

In the long division for 4489​, the first divisor is 6 (since 62=36) for the period 44. What is the very next divisor used (before placing the next digit)?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 8 Square Root by Long Division practice

In the long division for $4489$ , the first divisor is 6 (since $6^{2} = 36$ ) for the period 44. What is the very next divisor used (before placing the next digit)?