Practice30Create account

Express 49 as a sum of consecutive odd numbers starting from 1. How many odd numbers are needed?

Class 8Squares and Square RootsSquares and Roots
  • A7
  • B6
  • C14
  • D8

Step-by-Step Solution

49 = , and the sum of the first odd numbers equals . So 49 = 1 + 3 + 5 + 7 + 9 + 11 + 13, which is 7 odd numbers.
Answer: A) 7

Key idea: Properties of perfect squares

Useful patterns to spot a perfect square (and reject non-squares):

- **Last digit**: a perfect square ends in 0, 1, 4, 5, 6, or 9 — NEVER in 2, 3, 7, or 8. So 142 cannot be a perfect square (ends in 2).
- **Number of zeros at the end**: must be even. 100 is a perfect square ; 1000 is not.
- **Squares of even numbers are even; squares of odd numbers are odd.**
- **Sum of consecutive odd numbers**: 1 + 3 + 5 + … + . Try it: .

These let you reject many candidates without doing any heavy work.

Master this chapter in 30 minutes a day.

Don't just memorise the answer — build a daily practice habit.

Practice 5 Similar Questions Free →

All Squares and Square Roots practice questions

More Class 8 Squares and Square Roots practice

Which of the following is a Pythagorean triplet?For a Pythagorean triplet built from 2m, m² − 1, m² + 1, take m = 4. What is the largest…A school wants to arrange 2500 students in a square formation with equal rows and…How many non-perfect-square numbers lie between 16² and 17²? (Count the numbers strictly…Without adding, the value of 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 is: