- A13
- B7
- C91
- D8281
Step-by-Step Solution
1183 = 7 × , so , and . The trap 13 uses only the 13 pair and forgets the new 7 pair; 7 repeats the multiplier given in the question; and 8281 is the perfect square itself, not its root.
Answer: C) 91
The smallest number by which 1183 must be multiplied to give a perfect square is 7. What is the square root of that perfect square?
Class 8Squares and Square RootsSquares and Roots
Key idea: Properties of perfect squares
Useful patterns to spot a perfect square (and reject non-squares):
- **Last digit**: a perfect square ends in 0, 1, 4, 5, 6, or 9 — NEVER in 2, 3, 7, or 8. So 142 cannot be a perfect square (ends in 2).
- **Number of zeros at the end**: must be even. 100 is a perfect square ; 1000 is not.
- **Squares of even numbers are even; squares of odd numbers are odd.**
- **Sum of consecutive odd numbers**: 1 + 3 + 5 + … + . Try it: .
These let you reject many candidates without doing any heavy work.
- **Last digit**: a perfect square ends in 0, 1, 4, 5, 6, or 9 — NEVER in 2, 3, 7, or 8. So 142 cannot be a perfect square (ends in 2).
- **Number of zeros at the end**: must be even. 100 is a perfect square ; 1000 is not.
- **Squares of even numbers are even; squares of odd numbers are odd.**
- **Sum of consecutive odd numbers**: 1 + 3 + 5 + … + . Try it: .
These let you reject many candidates without doing any heavy work.
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