A temple hall has 10 round pillars, each of diameter 50 cm and height 3.5 m. Painting the curved surfaces costs ₹20 per sq m. What is the total cost? (Take π = 22/7.)

Question

Accepted Answer

₹1100. r = 0.25 m. One pillar: 2 × 22/7 × 0.25 × 3.5 = 5.5 sq m. Ten pillars: 55 sq m. Cost = 55 × 20 = ₹1100. Using 0.5 m as radius doubles it to ₹2200.

A temple hall has 10 round pillars, each of diameter 50 cm and height 3.5 m. Painting the curved surfaces costs ₹20 per sq m. What is the total cost? (Take π = $\frac{22}{7} .$ )

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 8 Surface Area of a Cylinder practice

A temple hall has 10 round pillars, each of diameter 50 cm and height 3.5 m. Painting the curved surfaces costs ₹20 per sq m. What is the total cost? (Take π = 722​.)

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 8 Surface Area of a Cylinder practice

A temple hall has 10 round pillars, each of diameter 50 cm and height 3.5 m. Painting the curved surfaces costs ₹20 per sq m. What is the total cost? (Take π = $\frac{22}{7} .$ )