Three consecutive integers are such that 5 times the smallest equals twice the largest plus twice the middle integer plus 6. Taking the smallest as x, find the three integers.

Question

Accepted Answer

12, 13, 14. Integers: x, x+1, x+2. Equation: 5x = 2(x+2) + 2(x+1) + 6 = 4x + 12. So 5x - 4x = 12, x = 12. The integers are 12, 13, 14. Check: 5(12) = 60 and 2(14) + 2(13) + 6 = 28 + 26 + 6 = 60.

Three consecutive integers are such that 5 times the smallest equals twice the largest plus twice the middle integer plus 6. Taking the smallest as $x$ , find the three integers.

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 8 Variables on Both Sides practice