Sanjay folds a square sheet to make a quadrilateral whose angles are (x + 10), (x + 30), (x + 50) and (x + 70) degrees. The angles form an increasing sequence. Find the measure of the second-smallest angle.

Question

Accepted Answer

80°. Sum = 4x + 160 = 360, so 4x = 200, x = 50. Angles: x+10=60, x+30=80, x+50=100, x+70=120. Second-smallest = 80°.

Sanjay folds a square sheet to make a quadrilateral whose angles are $(x + 10), (x + 30), (x + 50)$ and $(x + 70)$ degrees.
The angles form an increasing sequence.
Find the measure of the second-smallest angle.

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 9 Angle Sum Property of Quadrilaterals practice

Sanjay folds a square sheet to make a quadrilateral whose angles are (x+10),(x+30),(x+50) and (x+70) degrees.The angles form an increasing sequence.Find the measure of the second-smallest angle.

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 9 Angle Sum Property of Quadrilaterals practice

Sanjay folds a square sheet to make a quadrilateral whose angles are $(x + 10), (x + 30), (x + 50)$ and $(x + 70)$ degrees.
The angles form an increasing sequence.
Find the measure of the second-smallest angle.