A triangular piece of land has sides 41 m, 28 m and 15 m. The owner wishes to plant trees along the longest altitude (the altitude drawn to the longest side). First find the area (in m^2).

Question

Accepted Answer

126. s = 41+28+15/2 = 42. Area = √42 · (42-41) · (42-28) · (42-15) = √42 · 1 · 14 · 27 = √15876 = 126 m^2.

A triangular piece of land has sides 41 $m, 28 m$ and 15 $m$ .
The owner wishes to plant trees along the longest altitude (the altitude drawn to the longest side).
First find the area (in $m^{2}$ ).

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 9 Area of a Triangle by Heron's Formula practice

A triangular piece of land has sides 41 m,28m and 15 m.The owner wishes to plant trees along the longest altitude (the altitude drawn to the longest side).First find the area (in m2).

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 9 Area of a Triangle by Heron's Formula practice

A triangular piece of land has sides 41 $m, 28 m$ and 15 $m$ .
The owner wishes to plant trees along the longest altitude (the altitude drawn to the longest side).
First find the area (in $m^{2}$ ).