A triangular plot of a temple compound has sides 51 m, 37 m and 20 m. Garden lights are to be placed covering the entire area at 1 light per 6 m^2. How many lights (whole number) are needed to cover the area?

Question

Accepted Answer

51. s = 51+37+20/2 = 54. Area = √54 · (54-51) · (54-37) · (54-20) = √54 · 3 · 17 · 34 = √93636 = 306 m^2. Lights = 306/6 = 51.

A triangular plot of a temple compound has sides 51 m, 37 m and 20 m.
Garden lights are to be placed covering the entire area at 1 light per $6 m^{2}$ .
How many lights (whole number) are needed to cover the area?

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More Class 9 Area of a Triangle by Heron's Formula practice

A triangular plot of a temple compound has sides 51 m, 37 m and 20 m.Garden lights are to be placed covering the entire area at 1 light per 6m2.How many lights (whole number) are needed to cover the area?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 9 Area of a Triangle by Heron's Formula practice

A triangular plot of a temple compound has sides 51 m, 37 m and 20 m.
Garden lights are to be placed covering the entire area at 1 light per $6 m^{2}$ .
How many lights (whole number) are needed to cover the area?