A field is a parallelogram ABCD with area 360 m^2. P is the midpoint of side BC. Mr. Iyer fences triangle APD. Triangle APD has base AD and its apex P lies on the line through BC (parallel to AD). Find ar(APD) in m^2.

Question

Accepted Answer

180. P lies on BC, the parallel to AD. Triangle APD shares base AD with the parallelogram between the same parallels AD and BC, so ar(APD) = 1/2(360) = 180 m^2.

A field is a parallelogram ABCD with area $360 m^{2}$ . P is the midpoint of side BC. Mr. Iyer fences triangle APD. Triangle APD has base AD and its apex P lies on the line through BC (parallel to AD). Find ar(APD) in $m^{2}$ .

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More Class 9 Areas — Figures on the Same Base practice

A field is a parallelogram ABCD with area 360m2. P is the midpoint of side BC. Mr. Iyer fences triangle APD. Triangle APD has base AD and its apex P lies on the line through BC (parallel to AD). Find ar(APD) in m2.

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 9 Areas — Figures on the Same Base practice

A field is a parallelogram ABCD with area $360 m^{2}$ . P is the midpoint of side BC. Mr. Iyer fences triangle APD. Triangle APD has base AD and its apex P lies on the line through BC (parallel to AD). Find ar(APD) in $m^{2}$ .