Practice30Create account

ABCD is a parallelogram and X is a point on diagonal BD. Lines through X parallel to the sides create smaller parallelograms. By the same-base theorem, ar(triangle ABD) compared with ar(parallelogram ABCD) is:

Class 9Areas — Figures on the Same BaseGeometry
  • A
  • B
  • C
  • D

Step-by-Step Solution

Diagonal BD divides the parallelogram into two congruent triangles, so ar(ABD) = ar(ABCD).
Answer: A)

Master this chapter in 30 minutes a day.

Don't just memorise the answer — build a daily practice habit.

Practice 5 Similar Questions Free →

All Areas — Figures on the Same Base practice questions

More Class 9 Areas — Figures on the Same Base practice

A garden plot is a parallelogram of area 240 m^2 standing on base 20 m. A second…In triangle ABC, D and E are midpoints of AB and AC. DE is parallel to BC. Triangles BDE…In parallelogram PQRS, T is any point on side QR. PS = 13 cm and the distance between…A triangle ABC and a parallelogram ABDE are on the same base AB and between the same…Priya draws triangle ABC with area 96 cm^2. She marks D on BC such that BD : DC = 1 : 2,…