Triangles ABD and ACD lie on the same base AD. B and C are on opposite sides of line AD, each at perpendicular distance 5 cm from AD, and AD = 8 cm. The total area of quadrilateral ABDC (in cm^2) is:

Question

Accepted Answer

40. Each triangle = 1/2(8)(5) = 20 cm^2. They are on opposite sides of AD, so total area = 20 + 20 = 40 cm^2.

Triangles ABD and ACD lie on the same base AD. B and C are on opposite sides of line AD, each at perpendicular distance 5 cm from AD, and AD = 8 cm. The total area of quadrilateral ABDC (in $cm^{2}$ ) is:

Step-by-Step Solution

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More Class 9 Areas — Figures on the Same Base practice

Triangles ABD and ACD lie on the same base AD. B and C are on opposite sides of line AD, each at perpendicular distance 5 cm from AD, and AD = 8 cm. The total area of quadrilateral ABDC (in cm2) is:

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 9 Areas — Figures on the Same Base practice

Triangles ABD and ACD lie on the same base AD. B and C are on opposite sides of line AD, each at perpendicular distance 5 cm from AD, and AD = 8 cm. The total area of quadrilateral ABDC (in $cm^{2}$ ) is: