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Angle A of parallelogram ABCD exceeds angle B by 30°.
Find angle A (in degrees) using the adjacent-angle property.

Class 9Conditions for a ParallelogramGeometry — Quadrilaterals

A105
B95
C210
D115

Step-by-Step Solution

Let angle

B = b

. Then angle

A = b + 30

. Adjacent angles supplementary:

(b + 30) + b = 180, 2 b = 150, b = 75

. Angle

A = 75 + 30 = 105

deg.

Answer: A) 105

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