- AAB + AC
- BAB - AC
- CBC
- DAC only
Step-by-Step Solution
You cut off BD = AB + AC along the ray from B. The perpendicular bisector of DC then meets BD at A, so that AD = AC and BA + AC = BD as required.
Answer: A) AB + AC
In constructing a triangle from base BC and angle B with given AB + AC, after drawing BC and angle B you mark a point D on the ray so that BD equals:
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