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It is given that AB = CD and CD = EF (all are segment lengths). A student also notes that AB = EF.
The step 'AB = EF' is justified by which axiom?

Class 9Euclid's AxiomsGeometry — Foundations
  • AThings equal to the same thing are equal to one another
  • BThe whole is greater than the part
  • CThings which coincide are equal
  • DIf equals are added to equals the wholes are equal

Step-by-Step Solution

AB and EF are both equal to the same CD, hence AB = EF by the first axiom (transitivity).
Answer: A) Things equal to the same thing are equal to one another

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