In an experiment a die was rolled N times. The experimental probabilities recorded were: P(1) = 0.16, P(2) = 0.18, P(3) = 0.14, P(4) = 0.20, P(5) = 0.15. The number 6 came up 51 times. Find P(6) and then the total number of rolls N.

Question

Accepted Answer

P(6) = 0.17, N = 300. P(6) = 1 - (0.16+0.18+0.14+0.20+0.15) = 1 - 0.83 = 0.17. Since 51 rolls correspond to P = 0.17, N = 51/0.17 = 300.

In an experiment a die was rolled N times. The experimental probabilities recorded were:
P(1) = 0.16, P(2) = 0.18, P(3) = 0.14, P(4) = 0.20, P(5) = 0.15.
The number 6 came up 51 times.
Find P(6) and then the total number of rolls N.

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More Class 9 Experimental Probability practice

In an experiment a die was rolled N times. The experimental probabilities recorded were:P(1) = 0.16, P(2) = 0.18, P(3) = 0.14, P(4) = 0.20, P(5) = 0.15.The number 6 came up 51 times.Find P(6) and then the total number of rolls N.

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 9 Experimental Probability practice

In an experiment a die was rolled N times. The experimental probabilities recorded were:
P(1) = 0.16, P(2) = 0.18, P(3) = 0.14, P(4) = 0.20, P(5) = 0.15.
The number 6 came up 51 times.
Find P(6) and then the total number of rolls N.