- A55°
- B75°
- C25°
- D105°
Step-by-Step Solution
In △ABD, ∠ADC is an exterior angle: ∠ADC = 30° + 45° = 75°. In △ADC: ∠DAC = 180° − 75° − 50° = 55°.
Answer: A) 55°
In the figure, D lies on BC. ∠BAD = 30°, ∠B = 45° and ∠C = 50°. Find ∠DAC.
Class 9Exterior Angle of a TriangleGeometry — Lines and Angles
Master this chapter in 30 minutes a day.
Don't just memorise the answer — build a daily practice habit.
Practice 5 Similar Questions Free →All Exterior Angle of a Triangle practice questions
More Class 9 Exterior Angle of a Triangle practice
In △ABC, ∠B = 60° and ∠C = 40°. AD bisects ∠A and meets BC at D. Find ∠ADC.The exterior angles at B and C of △ABC add up to 250°. Find ∠A.The angles of a triangle are x, 2x and 3x. Find the exterior angle at the vertex whose…In △ABC, ∠A = x, ∠B = x + 10° and the exterior angle at C (BC produced) is 130°. Find…A roof truss is an isosceles triangle with a ridge (top) angle of 110°. The bottom tie…