Mr. Verma writes a polynomial p(x) = x^3 - 23x^2 + 142x - 120 and tells the class all roots are positive integers, the smallest being 1. Given (x - 1) is a factor and the quotient is x^2 - 22x + 120, find the LARGEST root.

Question

Accepted Answer

12. x^2 - 22x + 120 = (x - 10)(x - 12) since 10 + 12 = 22 and 10 x 12 = 120. Roots are 1, 10, 12; the largest is 12.

Mr. Verma writes a polynomial $p (x) = x^{3} - 23 x^{2} + 142 x - 120$ and tells the class all roots are positive integers, the smallest being 1.
Given $(x - 1)$ is a factor and the quotient is $x^{2} - 22 x + 120$ , find the LARGEST root.

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More Class 9 Factor Theorem and Factorisation practice

Mr. Verma writes a polynomial p(x)=x3−23x2+142x−120 and tells the class all roots are positive integers, the smallest being 1.Given (x−1) is a factor and the quotient is x2−22x+120, find the LARGEST root.

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 9 Factor Theorem and Factorisation practice

Mr. Verma writes a polynomial $p (x) = x^{3} - 23 x^{2} + 142 x - 120$ and tells the class all roots are positive integers, the smallest being 1.
Given $(x - 1)$ is a factor and the quotient is $x^{2} - 22 x + 120$ , find the LARGEST root.