A rectangle has corners (−3, −2), (5, −2), (5, y) and (−3, y) with y 0. Its area is 40 sq units. What is y?

Question

A rectangle has corners (−3, −2), (5, −2), (5, y) and (−3, y) with y > 0. Its area is 40 sq units. What is y?

Accepted Answer

3. Width = 5 − (−3) = 8, so height = 40 ÷ 8 = 5. The height runs from −2 up to y, so y = −2 + 5 = 3. (5 is the height, not the coordinate.)

A rectangle has corners (−3, −2), (5, −2), (5, $y$ ) and (−3, $y$ ) with $y$ > 0. Its area is 40 sq units. What is $y$ ?