Practice30Create account

Two adjacent corners of a square are (0, 0) and (5, 0). The square lies above the -axis. Where are its other two corners?

Class 9Figures on the Coordinate PlaneCoordinate Geometry
  • A(5, 5) and (0, 5)
  • B(0, 5) and (5, 0)
  • C(10, 0) and (10, 5)
  • D(5, −5) and (0, −5)

Step-by-Step Solution

The side length is 5. Going 5 units straight up from each corner gives (5, 5) and (0, 5). The option with −5 places the square below the -axis.
Answer: A) (5, 5) and (0, 5)

Master this chapter in 30 minutes a day.

Don't just memorise the answer — build a daily practice habit.

Practice 5 Similar Questions Free →

All Figures on the Coordinate Plane practice questions

More Class 9 Figures on the Coordinate Plane practice

A rhombus has its vertices at (0, 2), (5, 0), (0, −2) and (−5, 0). What is its area?The rhombus with vertices (0, 4), (3, 0), (0, −4) and (−3, 0) is shown. Find its…Which point lies exactly halfway between (2, 3) and (8, 3)?A vegetable plot on a grid (1 unit = 1 m) has corners (1, 2), (9, 2), (9, 7) and (1, 7).…A trapezium has vertices (0, 0), (10, 0), (7, 4) and (1, 4). What is its area?