A line passes through (0, 5) and falls so it reaches the x-axis at (10, 0). Aman wants the rupees-per-step relationship written as an equation in the form x/a + y/b = 1. Which equation is correct?

Question

Accepted Answer

x/10 + y/5 = 1. The x-intercept is 10 (a=10) and the y-intercept is 5 (b=5). Intercept form: x/10 + y/5 = 1.

A line passes through (0, 5) and falls so it reaches the $x$ -axis at (10, 0).
Aman wants the rupees-per-step relationship written as an equation in the form $\frac{x}{a} + \frac{y}{b} = 1$ .
Which equation is correct?

Step-by-Step Solution

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More Class 9 Graph of a Linear Equation practice

A line passes through (0, 5) and falls so it reaches the x-axis at (10, 0).Aman wants the rupees-per-step relationship written as an equation in the form ax​+by​=1.Which equation is correct?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 9 Graph of a Linear Equation practice

A line passes through (0, 5) and falls so it reaches the $x$ -axis at (10, 0).
Aman wants the rupees-per-step relationship written as an equation in the form $\frac{x}{a} + \frac{y}{b} = 1$ .
Which equation is correct?