An auto-rickshaw charges Rs 10 fixed plus Rs 5 per km. If y is the total fare for x km, the relation is y = 5x + 10. What is the fare (y) shown by the graph when the distance is x = 0 km?

Question

Accepted Answer

10. Put x = 0 in y = 5x + 10: y = 0 + 10 = 10. The y-intercept (0, 10) is the fixed charge.

An auto-rickshaw charges Rs 10 fixed plus Rs 5 per km. If $y$ is the total fare for $x$ km, the relation is $y = 5 x + 10$ .
What is the fare $(y)$ shown by the graph when the distance is $x = 0$ km?

Step-by-Step Solution

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More Class 9 Graph of a Linear Equation practice

An auto-rickshaw charges Rs 10 fixed plus Rs 5 per km. If y is the total fare for x km, the relation is y=5x+10.What is the fare (y) shown by the graph when the distance is x=0 km?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 9 Graph of a Linear Equation practice

An auto-rickshaw charges Rs 10 fixed plus Rs 5 per km. If $y$ is the total fare for $x$ km, the relation is $y = 5 x + 10$ .
What is the fare $(y)$ shown by the graph when the distance is $x = 0$ km?