Sides of a triangle are (x), (x + 2) and (x + 4) cm, where x is a positive integer. What is the smallest integer value of x for which the triangle exists?

Question

Accepted Answer

3. The two shorter sides must exceed the longest: x + (x+2) > x+4, so 2x+2 > x+4, x > 2. Smallest positive integer x = 3.

Sides of a triangle are $(x), (x + 2)$ and $(x + 4)$ cm, where $x$ is a positive integer.
What is the smallest integer value of $x$ for which the triangle exists?

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More Class 9 Inequalities in a Triangle practice

Sides of a triangle are (x),(x+2) and (x+4) cm, where x is a positive integer.What is the smallest integer value of x for which the triangle exists?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 9 Inequalities in a Triangle practice

Sides of a triangle are $(x), (x + 2)$ and $(x + 4)$ cm, where $x$ is a positive integer.
What is the smallest integer value of $x$ for which the triangle exists?