A factory in Surat records the number of defective items per batch over 10 batches: 4, 6, 4, 8, 4, 10, 6, 4, 12, 2. Let A = mean, B = median, C = mode. Arrange A, B, C in increasing order and give the value of (A + B + C).

Question

Accepted Answer

15. Sum = 4+6+4+8+4+10+6+4+12+2 = 60, so A (mean) = 60/10 = 6. Sorted: 2,4,4,4,4,6,6,8,10,12. Median B = 5th + 6th/2 = 4+6/2 = 5. Mode C = 4 (appears 4 times). Increasing order: C(4) < B(5) < A(6). Sum A+B+C = 6+5+4 = 15.

A factory in Surat records the number of defective items per batch over 10 batches:
4, 6, 4, 8, 4, 10, 6, 4, 12, 2.
Let A = mean, B = median, C = mode. Arrange A, B, C in increasing order and give the value of (A + B + C).

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More Class 9 Measures of Central Tendency practice

A factory in Surat records the number of defective items per batch over 10 batches:4, 6, 4, 8, 4, 10, 6, 4, 12, 2.Let A = mean, B = median, C = mode. Arrange A, B, C in increasing order and give the value of (A + B + C).

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 9 Measures of Central Tendency practice

A factory in Surat records the number of defective items per batch over 10 batches:
4, 6, 4, 8, 4, 10, 6, 4, 12, 2.
Let A = mean, B = median, C = mode. Arrange A, B, C in increasing order and give the value of (A + B + C).