AB || CD. A transversal cuts AB at P and CD at Q. Angles APQ = (2x + 15) deg and PQD = (3x - 25) deg lie between the parallels on the same side of the transversal (co-interior angles). Find x.

Question

Accepted Answer

38. Co-interior angles supplementary: (2x + 15) + (3x - 25) = 180, so 5x - 10 = 180, 5x = 190, x = 38.

AB || CD. A transversal cuts AB at P and CD at Q. Angles APQ = $(2 x + 15)$ deg and PQD = $(3 x - 25)$ deg lie between the parallels on the same side of the transversal (co-interior angles).
Find $x$ .

Step-by-Step Solution

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More Class 9 Parallel Lines and a Transversal practice

AB || CD. A transversal cuts AB at P and CD at Q. Angles APQ = (2x+15) deg and PQD = (3x−25) deg lie between the parallels on the same side of the transversal (co-interior angles).Find x.

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 9 Parallel Lines and a Transversal practice

AB || CD. A transversal cuts AB at P and CD at Q. Angles APQ = $(2 x + 15)$ deg and PQD = $(3 x - 25)$ deg lie between the parallels on the same side of the transversal (co-interior angles).
Find $x$ .