Bisectors are drawn for a pair of co-interior angles formed when a transversal cuts two parallel lines. Co-interior angles are A and B with A + B = 180°. The two bisectors meet at a point; the angle between them is A/2 + B/2. Find this angle (deg).

Question

Accepted Answer

90. A + B = 180, so A/2 + B/2 = A + B/2 = 180/2 = 90°. The bisectors of co-interior angles are perpendicular.

Bisectors are drawn for a pair of co-interior angles formed when a transversal cuts two parallel lines. Co-interior angles are A and $B$ with $A + B = 180$ deg.
The two bisectors meet at a point; the angle between them is $\frac{A}{2} + \frac{B}{2}$ . Find this angle (deg).

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More Class 9 Parallel Lines and a Transversal practice

Bisectors are drawn for a pair of co-interior angles formed when a transversal cuts two parallel lines. Co-interior angles are A and B with A+B=180 deg. The two bisectors meet at a point; the angle between them is 2A​+2B​. Find this angle (deg).

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 9 Parallel Lines and a Transversal practice

Bisectors are drawn for a pair of co-interior angles formed when a transversal cuts two parallel lines. Co-interior angles are A and $B$ with $A + B = 180$ deg.
The two bisectors meet at a point; the angle between them is $\frac{A}{2} + \frac{B}{2}$ . Find this angle (deg).