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A point lies in Quadrant II. Its distance from the $x$ -axis is 5 and from the $y$ -axis is 3.
What are its coordinates?

Class 9Plotting PointsCoordinate Geometry

A(-3, 5)
B(3, 5)
C(-5, 3)
D(3, -5)

Step-by-Step Solution

Distance from

y

-axis = |

x

| = 3 and Quadrant II needs

x

<0, so

x = - 3

. Distance from

x

-axis = |

y

| = 5 and

y

>0, so

y = 5

.

Answer: A) (-3, 5)

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