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A point P $(2 t - 4, t - 1)$ lies on the $x$ -axis. Find the value of $t$ , and then the abscissa of P.

Class 9Points on the AxesCoordinate Geometry

At = 1, abscissa = -2
Bt = 1, abscissa = 0
Ct = 4, abscissa = 4
Dt = -1, abscissa = -6

Step-by-Step Solution

On the

x

-axis the ordinate is 0:

t - 1 = 0 \Rightarrow t = 1

. Then abscissa =

2 t - 4 = 2 (1) - 4 = - 2

.

Answer: A) t = 1, abscissa = -2

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