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For parallelogram ABCD, angle B = 100°.
P is a point on AB such that DP bisects angle ADC.
Find angle ADP (in degrees).

Class 9Properties of a ParallelogramGeometry — Quadrilaterals

A55
B50
C100
D45

Step-by-Step Solution

angle ADC = angle

B = 100

deg (opposite angles). DP bisects it: angle ADP =

\frac{100}{2} = 50

deg.

Answer: B) 50

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