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Let AB = AC in triangle ABC, and let D be a point on BC. From D, perpendiculars DP and DQ are drawn to AB and AC respectively.
Given angle B = angle C = 64°, find angle PDB, in degrees.

Class 9Properties of Isosceles TrianglesGeometry — Triangles
  • A52
  • B29
  • C23
  • D26

Step-by-Step Solution

In right triangle PBD, angle DPB = 90° and angle PBD = 64°, so angle PDB = 180 - 90 - 64 = 26°.
Answer: D) 26

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