If x = √3 - 1√3 + 1 and y = √3 + 1√3 - 1, find x + y.

4. x = (√3-1)^2/((3)-1) = 3 - 2√3 + 12 = 4 - 2√32 = 2 - √3. y = (√3+1)^2/2 = 4 + 2√32 = 2 + √3. x + y = 4.

If $x = \frac{3 - 1}{3 + 1}$ and $y = \frac{3 + 1}{3 - 1}$ , find $x + y$ .

Class 9Rationalising the DenominatorNumber Systems

x = (3 - 1)^{2} / ((3) - 1) = \frac{3 - 2 3 + 1}{2} = \frac{4 - 2 3}{2} = 2 - 3 . y = (3 + 1)^{\frac{2}{2}} = \frac{4 + 2 3}{2} = 2 + 3 . x + y = 4

Answer: B) 4

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