A surveyor marks pegs on a straight road treated as a number line (in km). Peg A is at -1.5, peg B is at 4.5. He must place peg C so that the distance AC is to CB as 1 is to 2 (AC:CB = 1:2). At what km mark should peg C be placed?

Question

Accepted Answer

0.5. Total AB = 4.5 - (-1.5) = 6 km. AC:CB = 1:2 means AC = 1/3(6) = 2 km. C = -1.5 + 2 = 0.5 km.

A surveyor marks pegs on a straight road treated as a number line (in km). Peg A is at -1.5, peg B is at 4.5. He must place peg C so that the distance AC is to CB as 1 is to 2 (AC:CB = 1:2). At what km mark should peg C be placed?

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