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Square ABCD has an equilateral triangle BCE drawn outside it on side BC. Find ∠AEB.

Class 9Rectangle, Rhombus and SquareGeometry — Quadrilaterals
  • A30°
  • B45°
  • C75°
  • D15°

Step-by-Step Solution

AB = BC = BE, so △ABE is isosceles. ∠ABE = 90° + 60° = 150°, so ∠AEB = (180° − 150°) ÷ 2 = 15°.
Answer: D) 15°

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