A factory's defect count is p(x) = 2x^3 - 9x^2 + 13x - 6 for batch number x. Using the Remainder Theorem, find the remainder when p(x) is divided by (2x - 3).

Question

Accepted Answer

0. 2x - 3 = 0 gives x = 3/2. p(3/2) = 2(27/8) - 9(9/4) + 13(3/2) - 6 = 27/4 - 81/4 + 39/2 - 6 = -54/4 + 78/4 - 24/4 = 0.

A factory's defect count is $p (x) = 2 x^{3} - 9 x^{2} + 13 x - 6$ for batch number $x$ .
Using the Remainder Theorem, find the remainder when $p (x)$ is divided by $(2 x - 3)$ .

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More Class 9 Remainder Theorem practice

A factory's defect count is p(x)=2x3−9x2+13x−6 for batch number x.Using the Remainder Theorem, find the remainder when p(x) is divided by (2x−3).

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 9 Remainder Theorem practice

A factory's defect count is $p (x) = 2 x^{3} - 9 x^{2} + 13 x - 6$ for batch number $x$ .
Using the Remainder Theorem, find the remainder when $p (x)$ is divided by $(2 x - 3)$ .