- A80°
- B100°
- C50°
- D160°
Step-by-Step Solution
AB = AD, ∠BAC = ∠DAC, AC common → △ABC ≅ △ADC (SAS). By CPCT, ∠ADC = ∠ABC = 100°.
Answer: B) 100°
In a kite ABCD, AB = AD and diagonal AC bisects ∠BAD. If ∠ABC = 100°, what is ∠ADC?
Class 9SAS, ASA and AAS CongruenceGeometry — Triangles
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