- AAAS
- BASA using AM = AN
- CSSS
- DSAS
Step-by-Step Solution
∠MAP = ∠NAP (bisector), ∠AMP = ∠ANP = 90°, and AP is common — it is opposite the right angles, not between the two angles. So AAS, and PM = PN.
Answer: A) AAS
P lies on the bisector of ∠BAC. PM and PN are perpendiculars from P to AB and AC. Which rule gives △AMP ≅ △ANP?
Class 9SAS, ASA and AAS CongruenceGeometry — Triangles
Master this chapter in 30 minutes a day.
Don't just memorise the answer — build a daily practice habit.
Practice 5 Similar Questions Free →All SAS, ASA and AAS Congruence practice questions
More Class 9 SAS, ASA and AAS Congruence practice
P is on the bisector of ∠A, and its perpendicular distance from arm AB is 4 cm. What is…In △ABC, D is the mid-point of BC. BE and CF are perpendiculars from B and C to line AD…Two equal ladders lean against a vertical wall, each making the same angle with the…Two right triangles have equal hypotenuses and one equal acute angle. Are they congruent?In △ABC, AB = AC. Points D on AB and E on AC are chosen so that AD = AE. By which rule…