A hemispherical bowl of internal radius 14 cm is filled and then closed with a flat circular lid that exactly covers the top. The craftsman polishes the inner curved surface and the lid's lower face. Find the total polished area (take π = 22/7). (CSA = curved surface area, TSA = total surface area)

Question

Accepted Answer

1848 cm^2. Inner curved surface = 2*π*r^2 = 2*(22/7)*196 = 1232 cm^2. Lid's lower face = π*r^2 = (22/7)*196 = 616 cm^2. Total = 1232 + 616 = 1848 cm^2 (this equals 3*π*r^2, the TSA).

A hemispherical bowl of internal radius 14 cm is filled and then closed with a flat circular lid that exactly covers the top.
The craftsman polishes the inner curved surface and the lid's lower face.
Find the total polished area (take π = 22/7). (CSA = curved surface area, TSA = total surface area)

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More Class 9 Surface Area of a Sphere practice

A hemispherical bowl of internal radius 14 cm is filled and then closed with a flat circular lid that exactly covers the top.The craftsman polishes the inner curved surface and the lid's lower face.Find the total polished area (take π = 22/7). (CSA = curved surface area, TSA = total surface area)

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 9 Surface Area of a Sphere practice