A solid metal sphere of radius 6 cm is melted and recast into a solid hemisphere. Using the fact that volume stays the same, the radius R of the hemisphere satisfies 2/3*π*R^3 = 4/3*π*6^3. Find R, then find the CSA of the hemisphere (leave answer as a multiple of π). (CSA = curved surface area, TSA = total surface area)

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Accepted Answer

2*π*(6*3√2)^2 cm^2. Equating volumes: R^3 = 2 * 6^3, so R = 6 * 3√2. CSA = 2*π*R^2 = 2*π*(6*3√2)^2 cm^2.

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