Two lines AB and CD are cut by a transversal PQ. The interior angles on the right side measure 65° and 110°. By how many degrees does the sum of these two interior angles fall short of 180°?

Question

Accepted Answer

5. Sum = 65 + 110 = 175°. Difference from 180 = 180 - 175 = 5°. Since the sum (175) is less than 180, the lines meet on the right side. The required difference is 5.

Two lines AB and CD are cut by a transversal PQ. The interior angles on the right side measure 65° and 110°.
By how many degrees does the sum of these two interior angles fall short of 180°?

Step-by-Step Solution

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More Class 9 The Fifth Postulate practice

Two lines AB and CD are cut by a transversal PQ. The interior angles on the right side measure 65° and 110°.By how many degrees does the sum of these two interior angles fall short of 180°?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 9 The Fifth Postulate practice

Two lines AB and CD are cut by a transversal PQ. The interior angles on the right side measure 65° and 110°.
By how many degrees does the sum of these two interior angles fall short of 180°?